Ex.No:6c Swap two numbers using call by reference
AIM:
To write a C program to swap two numbers using call by reference.
ALGORITHM:
Step 1: Start the program.
Step 2: Set a ← 10 and b ← 20
Step 3: Call the function swap(&a,&b)
Step 3a: Start fuction
Step 3b: Assign t ← *x
Step 3c: Assign *x ← *y
Step 3d: Assign *y ← t
Step 3e: End function
Step 4: Print x and y.
Step 5: Stop the program.
PROGRAM CODE:
#include<stdio.h> #include<conio.h> void swap(int *,int *); // Declaration of function void main( ) { int a = 10, b = 20 ; clrscr(); printf("n Before swapping"); printf( "n a = %d b = %d", a, b ); swap(&a,&b); // call by reference printf("n After swapping"); printf( "n a = %d b = %d", a, b ); getch(); } void swap( int *x, int *y ) { int t; t = *x; *x = *y; *y = t; }
OUTPUT:
RESULT:
Thus the C program to swap two numbers using call by reference is written and executed successfully.