# C program to find Transpose of a Matrix

Before going to the program first let us understand what is *Transpose of a Matrix*?

**Transpose of a matrix:**

* Transpose of a Matrix *is a matrix that is obtained by interchanging the rows and columns of a matrix.

*Transpose of a Matrix* can also be obtained by reflecting the elements along its main diagonal. Repeating the process on the transposed matrix returns the elements to their original position.

For Example,

Let the **matrix** be

1 2 3

4 5 6

7 8 9

Then the **Transpose** of the above **matrix** is

1 4 7

2 5 8

3 6 9

## Program Code to Transpose of a matrix in C:

#include <stdio.h> #include<conio.h> void main() { int a[10][10],b[10][10],i,j,r,c,tr,tc; clrscr(); printf("\n Enter the number of rows and columns of matrix : "); scanf("%d%d",&r,&c); printf("\n Enter the elements of matrix \n"); for( i = 0 ; i < r ; i++ ) { for( j = 0 ; j < c ; j++ ) { scanf("%d",&a[i][j]); } } tr=c; tc=r; for( i = 0 ; i < tr ; i++ ) { for( j = 0 ; j < tc ; j++ ) { b[i][j] = a[j][i]; } } printf("\n Transpose of matrix is \n\n"); for( i = 0 ; i < tr ; i++ ) { for( j = 0 ; j < tc ; j++ ) { printf(" %d ",b[i][j]); } printf("\n"); } getch(); }

## Working:

- First the computer reads the rows and columns of
**matrix**from the user. - Then using for loops the computer reads the
**matrix**from the user. - Then using for loops the
**transpose of a matrix**is carried out. - Finally using for loops the
**transposed matrix**is printed.

## Step by step working of the above program:

- Let us assume that a user enters the number of rows and columns as 3 and 3 respectively.
- And then enters the elements of matrix as given below

1 2 3

4 5 6

7 8 9

- tr=c (tr=3) , tc=r (tc=3)
- It assigns the value of i=0 and j=0 and the loop continues till condition of the for loop is true.

4.1. i<tr (0<3) for loop condition is true

4.1.1. j<tc (0<3) for loop condition is true

b[i][j]=a[j][i] (b[0][0]=a[o][o]) So b[0][0]=1

j++ (j=j+1) So j=1

4.1.2. j<tc (1<3) for loop condition is true

b[i][j]=a[j][i] (b[0][1]=a[1][o]) So b[0][1]=4

j++ (j=j+1) So j=2

4.1.3. j<tc (2<3) for loop condition is true

b[i][j]=a[j][i] (b[0][2]=a[2][o]) So b[0][2]=7

j++ (j=j+1) So j=3

4.1.4. j<tc (3<3) for loop condition is false

It comes out of the for loop and increment the value of i and reassigns the value of j.

i++ (i=i+1) So i=1 , j=0

4.2. i<tr (1<3) for loop condition is true

4.2.1. j<tc (0<3) for loop condition is true

b[i][j]=a[j][i] (b[1][0]=a[o][1]) So b[1][0]=2

j++ (j=j+1) So j=1

4.2.2. j<tc (1<3) for loop condition is true

b[i][j]=a[j][i] (b[1][1]=a[1][1]) So b[1][1]=5

j++ (j=j+1) So j=2

4.2.3. j<tc (2<3) for loop condition is true

b[i][j]=a[j][i] (b[1][2]=a[2][1]) So b[1][2]=8

j++ (j=j+1) So j=3

4.2.4. j<tc (3<3) for loop condition is false

It comes out of the for loop and increment the value of i and reassigns the value of j.

i++ (i=i+1) So i=2 , j=0

4.3. i<tr (2<3) for loop condition is true

4.3.1. j<tc (0<3) for loop condition is true

b[i][j]=a[j][i] (b[2][0]=a[o][2]) So b[2][0]=3

j++ (j=j+1) So j=1

4.3.2. j<tc (1<3) for loop condition is true

b[i][j]=a[j][i] (b[2][1]=a[1][2]) So b[2][1]=6

j++ (j=j+1) So j=2

4.3.3. j<tc (2<3) for loop condition is true

b[i][j]=a[j][i] (b[2][2]=a[2][2]) So b[2][2]=9

j++ (j=j+1) So j=3

4.3.4. j<tc (3<3) for loop condition is false

It comes out of the for loop and increment the value of i and reassigns the value of j.

i++ (i=i+1) So i=3 , j=0

4.4. i<tr (3<3) for loop condition is false

It comes out of the for loop.

- Finally using two for loops it prints the elements of the transpose matrix.
- Thus the program execution is completed.

## Output:

### DOWNLOAD THE PROGRAM CODE : CLICK HERE